Question

A circular bar is subjected to an axial pull of 150 kn. if the maximum intensity of shear stress on any oblique plane is not to exceed 75 mn/m square. determine the diameter of the bar

Answer 1

The diameter of the circular bar is approximately 29.35 mm.

Step-by-step explanation:

To determine the diameter of the circular bar, we need to use the maximum intensity of shear stress and the axial pull applied to the bar. The formula to calculate the shear stress on any oblique plane is given by:

Shear Stress = Pulling Force / Area

To find the area, we can use the formula for the area of a circle, which is π * (diameter/2)^2. Rearranging the equation, we can solve for the diameter:

Diameter = √(4 * (Pulling Force / Max Shear Stress) / π)

Substituting the given values, we get:

Diameter = √(4 * (150000 N) / (75 * 10^6 N/m^2 * 10^6 mm^2))

Diameter ≈ 29.35 mm