asked 128k views
5 votes
In a certain game, suppose there is no cost to playing the game, and a player has a probability 0.03 of winning a prize worth 829 , and a probability of 0.28 of winning another prize worth 68 . what is the expected payment of playing the game?

Options:
a. $24.13
b. $25.15
c. $27.34
d. $28.72

1 Answer

5 votes

Final answer:

The expected payment of playing the game is $43.91.

Step-by-step explanation:

To find the expected payment of playing the game, we need to multiply the probability of winning each prize by the value of the prize and sum them up.

Let's calculate:

Expected payment = (probability of winning prize 1 * value of prize 1) + (probability of winning prize 2 * value of prize 2)

Expected payment = (0.03 * 829) + (0.28 * 68)

Expected payment = 24.87 + 19.04

Expected payment = 43.91

Therefore, the expected payment of playing the game is $43.91.

answered
User Mogelbrod
by
8.0k points

Related questions

asked Aug 16, 2019 56.5k views
CheeHow asked Aug 16, 2019
by CheeHow
7.9k points
1 answer
5 votes
56.5k views
asked Apr 23, 2024 55.6k views
Omiz asked Apr 23, 2024
by Omiz
8.0k points
1 answer
5 votes
55.6k views
1 answer
3 votes
136k views
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.