Question

What was the work done during a 30m movement when a 120 N push is applied to the handle of a lawnmower, making a 30° angle with the floor?

a. 60 J
b. 90 J
c. 105 J
d. 120 J

Answer 1

To find the work done when a 120 N push is applied to the handle of a lawnmower, you need to calculate the dot product of the force vector and the displacement vector.

Step-by-step explanation:

To find the work done when a 120 N push is applied to the handle of a lawnmower, you need to calculate the dot product of the force vector and the displacement vector.

First, find the horizontal component of the force by multiplying the force by the cosine of the angle: F_h = 120 N * cos(30°) = 103.923 N

Then, multiply the horizontal component of the force by the displacement to find the work done: Work = F_h * 30 m = 103.923 N * 30 m = 3117.69 J

Therefore, the work done during the 30 m movement when a 120 N push is applied to the handle of a lawnmower is approximately 3117.69 J.