Final answer:
The amount of silver that can be recovered from 124 g of Ag₂S is approximately 107.22 g.
Step-by-step explanation:
To calculate the amount of silver that can be recovered from Ag₂S, we need to first determine the molar mass of Ag₂S. Ag has a molar mass of 107.87 g/mol, and S has a molar mass of 32.07 g/mol. So, the molar mass of Ag₂S is 107.87 g/mol * 2 + 32.07 g/mol = 247.81 g/mol.
Next, we can use the molar mass of Ag₂S to calculate the amount of silver in 124 g of Ag₂S using the following formula:
Amount of silver = (mass of Ag₂S / molar mass of Ag₂S) * (2 moles of Ag / 1 mole of Ag₂S)
Substituting the values, we get: Amount of silver = (124 g / 247.81 g/mol) * (2 moles of Ag / 1 mole of Ag₂S) = 0.995 moles of Ag.
Finally, we can convert moles of Ag to grams using the molar mass of Ag, which is 107.87 g/mol: Mass of silver = 0.995 moles of Ag * 107.87 g/mol = 107.22 g.