Final answer:
To find the number of liters of sulfur trioxide formed when 4800 cm3 of sulfur dioxide is burned in air, we can use the balanced chemical equation. The volume of sulfur trioxide formed will be the same as the volume of sulfur dioxide. Therefore, the correct answer is d. 4800 L.
Step-by-step explanation:
To find the number of liters of sulfur trioxide formed when 4800 cm3 of sulfur dioxide is burned in air, we need to consider the balanced chemical equation:
2SO2 (g) + O2 (g) → 2SO3 (g)
From the equation, we can see that for every two moles of sulfur dioxide (SO2), two moles of sulfur trioxide (SO3) are formed. This means that the volume of sulfur trioxide formed will be the same as the volume of sulfur dioxide. Converting 4800 cm3 to liters, we get 4.8 L.
Therefore, the correct answer is d. 4800 L.