Question

Determine the mass of a ball with a wavelength of 3.45 × 10-34 m and a velocity of 6.55 m/s1. Write a balanced chemical equation, including physical state symbols, for the combustion of gaseous methane into gaseous carbon dioxide and gaseous water.

Answer 1

The mass of the ball is approximately 2.95 × 10^-3 kg using de Broglie wavelength formula. The balanced chemical equation for the combustion of gaseous methane is CH4(g) + 2O2(g) → CO2(g) + 2H2O(g).

Step-by-step explanation:

To determine the mass of a ball with a wavelength of 3.45 × 10^-34 m and a velocity of 6.55 m/s, we can use the de Broglie wavelength formula λ = h/mv, where λ is the wavelength, h is Planck's constant (6.62607015 × 10^-34 Js), m is the mass, and v is the velocity. Solving for mass (m), we rearrange the formula to m = h/λv:

m = (6.62607015 × 10^-34 Js) / (3.45 × 10^-34 m × 6.55 m/s)

After calculating, the mass (m) of the ball is found to be approximately 2.95 × 10^-3 kg.

For the balanced chemical equation for the combustion of gaseous methane:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Here, methane (CH4) reacts with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O), all in their gaseous state.