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At equilibrium at 1200°C, [I2] = 9.5 ×10^(-2) m and [I] = 3.2 × 10^(-2) m. What is the value of Keq for this system?

a. 3.4 × 10^(-1)
b. 1.1 × 10^(-2)
c. 1.1
d. 93

asked
User Cassius
by
7.6k points

1 Answer

6 votes

Final answer:

Using the provided equilibrium concentrations, the equilibrium constant (Keq) for the reaction I2(g) ⇌ 2I(g) is calculated. The Keq is found by squaring the concentration of I and dividing by the concentration of I2, resulting in an answer of 1.1 × 10⁻².

Step-by-step explanation:

The student is asking for the equilibrium constant (Keq) of a chemical reaction involving iodine and iodide at a specific temperature. This is a classic chemistry problem involving the concept of chemical equilibrium.

To find the Keq, one must use the equilibrium concentrations of the products and reactants in the reaction's equilibrium constant expression, which for the general reaction aA + bB ⇌ cC + dD is Keq = [C]³ [D]³ / [A]³ [B]³. For the reaction I₂(g) ⇌ 2I(g), the equilibrium expression is Keq = [I]² / [I₂]. Given the equilibrium concentrations, [I₂] = 9.5 × 10⁻² M and [I] = 3.2 × 10⁻² M, we can substitute these into the expression and solve for Keq:

Keq = (1.3.2 × 10⁻² M)² / (9.5 × 10⁻² M)

Keq = (1.024 × 10⁻3 M²) / (9.5 × 10⁻² M)

Keq = 1.1 × 10⁻²

Therefore, the correct answer is b. 1.1 × 10⁻².

answered
User AnHeuermann
by
8.8k points
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