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Snowy's Snow Cones has a special bubble gum snow cone on sale. The cone is a regular snow cone that has a spherical piece of bubble gum nested at the bottom of the cone. The radius of the snow cone is 4 inches, and the height of the cone is 6 inches. If the diameter of the bubble gum is 0.8 inches, which of the following can be used to calculate the volume of the cone that can be filled with flavored ice?

Option 1: 1/3(3.14)(6^2)(4) - 4/3(3.14)(0.43)
Option 2: 1/3(3.14)(4^2)(6) - 4/3(3.14)(0.43)
Option 3: 1/3(3.14)(6^2)(4) - 4/3(3.14)(0.83)
Option 4: 1/3(3.14)(4^2)(6) - 4/3(3.14)(0.83)

asked
User Sneaksta
by
8.0k points

1 Answer

4 votes

Final answer:

To calculate the volume of the cone that can be filled with flavored ice, you can use the formula for the volume of a cone: V = 1/3(πr^2h), where r is the radius and h is the height. Option 2: 1/3(3.14)(4^2)(6) - 4/3(3.14)(0.43) can be used to calculate the volume of the cone in this particular scenario.

Step-by-step explanation:

To calculate the volume of the cone that can be filled with flavored ice, we can use the formula for the volume of a cone: V = 1/3(πr^2h), where r is the radius and h is the height. Since the radius of the snow cone is 4 inches and the height is 6 inches, we can substitute these values into the formula to get the volume of the cone. To determine the volume of the bubble gum, we can use the formula for the volume of a sphere: V = 4/3(πr^3), where r is the radius of the bubble gum. Since the diameter of the bubble gum is given as 0.8 inches, we can use this value to calculate the radius and then substitute it into the formula to get the volume of the bubble gum.

Option 1: 1/3(3.14)(6^2)(4) - 4/3(3.14)(0.43)
Option 2: 1/3(3.14)(4^2)(6) - 4/3(3.14)(0.43)
Option 3: 1/3(3.14)(6^2)(4) - 4/3(3.14)(0.83)
Option 4: 1/3(3.14)(4^2)(6) - 4/3(3.14)(0.83)

Based on the formulas and the given values, Option 2: 1/3(3.14)(4^2)(6) - 4/3(3.14)(0.43) can be used to calculate the volume of the cone that can be filled with flavored ice.

answered
User Nathan Fritz
by
8.9k points
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