Question

Pls help asap question in attachment

Answer 1

`\qquad\qquad\huge\underline{{\sf Answer}}♨`

Let's use similarity here :

The given triangles are similar to one another by AA criteria, since they are parallel, hence two of the angles of 1st triangle are equal to that of 2nd triangle.

that is :

`\qquad \sf\angle EKP = \angle EHL \: \: \: (corrosponding)`

`\qquad \sf\angle EPK = \angle ELH \: \: \: (corrosponding)`

so,

`\therefore \qquad \sf\triangle EKP \sim \triangle EHL \: \: \: \: (aa \: \: criteria)`

Now, let's use its results ~

`\therefore \sf \qquad(EK)/(EH) = (EP)/(EL)`

Answer 2

Explanation:

they are similar triangles and angle EKP and EHL is 90 and angle HEL and KEP is the same so the angles of triangle KEP and HEL are the same and they are similar to each other.