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If a solid disk of mass m=0.9 kg and radius r=0.45 m is suspended vertically and is free to rotate about its center without friction, what is the angular acceleration when a point object is placed at an angle θ=35∘ clockwise from the top along the rim? a) 0.45 rad/s2 b) 0.72 rad/s2 c) 1.02 rad/s2 d) 1.28 rad/s2

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Without the force exerted by the point object or additional information, the angular acceleration of the solid disk cannot be calculated from the information provided.

The question pertains to the angular acceleration of a solid disk when a point object is placed at an angle along the rim. To find the angular acceleration, we would typically use Newton's second law for rotation, Τ = Iα, where Τ is the torque, I is the moment of inertia, and α is the angular acceleration. However, without the force exerted by the point object or additional information, we cannot calculate the angular acceleration. Normally, the point object's mass and the force of gravity would create a torque that could be used to find α. Since essential information is missing from the question provided, we cannot determine the correct angular acceleration of the disk in this specific scenario.

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User Muzer
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