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What is the percent concentration by mass/volume of 102.3 ml of a solution that contains 53.9 g of barium fluoride?

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User Weimar
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1 Answer

1 vote

Final answer:

The percent concentration by mass/volume of a solution containing 53.9 g of barium fluoride in 102.3 ml of solution is calculated as (53.9 g / 102.3 mL) × 100%, which equals to 52.693%.

Step-by-step explanation:

Calculating Percent Concentration by Mass/Volume

To determine the percent concentration by mass/volume of a solution containing 53.9 g of barium fluoride in 102.3 ml of solution, you first need to understand that mass/volume percent is calculated by taking the mass of the solute (in this case, barium fluoride) and dividing it by the volume of the solution, then multiplying by 100 to get a percentage. Therefore, the formula we will use is:

% m/v = (mass of solute in grams ÷ volume of solution in mL) × 100%

Plugging in the given values:

% m/v = (53.9 g ÷ 102.3 mL) × 100% = 52.693%

Thus, the solution has a percent concentration by mass/volume of 52.693%.

answered
User Yann Masoch
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7.7k points
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