Question

Consider the graph of the equation below. Her would the vertex be? y = (x - 3)^2 + 4

Answer 1

The vertex of the quadratic is at the point (3, 4)

How to find the vertex of the quadratic?

For a quadratic with a vertex (h, k) and a leading coefficient a, we can write:

y = a*(x - h)² + k

Here we have the function:

y = (x - 3)² + 4

First we can see that the vertex is at the point (3, 4), also, notiice that the leading coefficient is positive, which means that the vertex is the minimum of the function.