Question

What does the scale read if the 95 kg cheerleader lifts the 50 kg cheerleader upward with an acceleration of 2.0 m/s2.

Answer 1

The scale will read 450 N.

Step-by-step explanation:

To solve this problem, we can use Newton's second law, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

In this case, we have a 95 kg cheerleader lifting a 50 kg cheerleader with an acceleration of 2.0 m/s². The net force on the system is equal to the product of the total mass of the system and the acceleration:

F_net = (m_1 + m_2) * a

F_net = (95 kg + 50 kg) * 2.0 m/s²

F_net = 225 kg * 2.0 m/s²

F_net = 450 N

Therefore, the scale will read 450 N.