Question

Identify the vertical asymptotes of f(x) = quantity x minus 4 over quantity x squared plus 13 x plus 36.

a) x = −9 and x = −4
b) x = −9 and x = 4
c) x = 9 and x = −4
d) x = 9 and x = 4

Answer 1

The vertical asymptotes of the function f(x) = (x - 4)/(x^2 + 13x + 36) are x = -4 and x = -9.

Step-by-step explanation:

The vertical asymptotes can be found by determining the values of x for which the denominator of the function is equal to zero. In this case, the denominator is (x^2 + 13x + 36). We can factor this expression to get (x + 4)(x + 9) = 0. So, the vertical asymptotes occur at x = -4 and x = -9.