Question

Given the following reaction:

2CH₃OH(l)+3O₂(g)---> 2CO₂(g)+ 4H₂O(g)
What is the energy change when 32.8 g of CH_3OH react with excess O₂ ?

Answer 1

To find the energy change for the reaction of 32.8 g of CH3OH, the number of moles of CH3OH must first be calculated. Then, using the enthalpy change per mole (ΔH), we could calculate the total energy change. However, without the ΔH value provided, a numerical answer cannot be calculated.

Step-by-step explanation:

To calculate the energy change when 32.8 g of methanol (CH3OH) reacts, we need to know the enthalpy change for the given chemical reaction. Unfortunately, the enthalpy change (ΔH) is not provided in the question. Typically this value would be given or available in a standard enthalpies of formation table. In such a case, we would take the following general steps:

1. Calculate the number of moles of CH3OH based on its molar mass (32.04 g/mol): moles = mass (32.8 g) / molar mass (32.04 g/mol).
2. Use the stoichiometry of the balanced chemical equation to determine the amount of heat energy (Q) per mole of CH3OH reacted, which would be given as the enthalpy change.
3. Calculate the total energy change by multiplying the moles of CH3OH by the enthalpy change per mole. Q = moles * ΔH.

Without the actual enthalpy change value for the reaction, it is not possible to provide a numerical answer.