Final answer:
It will take approximately 6.12 seconds for the golf ball to land.
Step-by-step explanation:
To determine how long it will take for a golf ball launched at 60° at 35m/s to land, we can use the equations of projectile motion. First, we need to break down the initial velocity into its horizontal and vertical components. The vertical component of the velocity is given by the formula Vy = Vsinθ, where V is the initial speed and θ is the launch angle. In this case, Vy = 35m/s * sin(60°) = 30m/s. The time it takes for the ball to reach its maximum height can be found using the formula t = Vy / g, where g is the acceleration due to gravity, approximately 9.8m/s^2. Substituting the values, t = 30m/s / 9.8m/s^2 = 3.06s.
Now, the time it takes for the ball to land can be found by doubling the time it takes for the ball to reach its maximum height. So, the total time of flight is T = 2 * t = 2 * 3.06s = 6.12s. Therefore, it will take approximately 6.12 seconds for the golf ball to land.