Question

A 20-milliliter sample of a gas is at 546 K and has a pressure of 6.0 atmospheres. If the temperature is changed to 273 K and the pressure to 2.0 atmospheres, the new volume of the gas will be?

A) 3.3 mL
B) 13 mL
C) 30 mL
D) 120 mL

Answer 1

The new volume of the gas will be 0.02 L or 20 mL.

Step-by-step explanation:

To solve this problem, we can use the combined gas law formula:

P1V1 / T1 = P2V2 / T2

Given:

• P1 = 6.0 atm
• V1 = 20 mL = 0.02 L
• T1 = 546 K
• P2 = 2.0 atm
• T2 = 273 K

Substituting the values into the formula:

(6.0 atm)(0.02 L) / (546 K) = (2.0 atm)(V2) / (273 K)

Solving for V2, we get:

V2 = (6.0 atm)(0.02 L)(273 K) / (2.0 atm)(546 K) = 0.02 L

The new volume of the gas is 0.02 L, which is equal to 20 mL.