Question

Larry, Moe, and Curly went bowling. Moe was the winner! Larry's score was half of Moe's score. Curly lost to Moe by 10 pins. If their combined score was 590 pins, what was each person's individual score?

Answer 1

Larry's score was 120 pins, Moe's score was 240 pins, and Curly's score was 230 pins.

Step-by-step explanation:

Let's denote Larry's score as L, Moe's score as M, and Curly's score as C.

We are given that Moe's score is the highest, and Larry's score is half of Moe's score, so L = 0.5M.

We are also given that Curly's score is 10 pins less than Moe's score, so C = M - 10.

The sum of their scores is 590, so L + M + C = 590.

Substituting the values for L and C in terms of M, we have:

0.5M + M + (M - 10) = 590

Combining like terms, we get 2.5M - 10 = 590.

Adding 10 to both sides and dividing by 2.5, we find M = 240.

Substituting this value back into the equations for L and C, we find L = 120 and C = 230.

Therefore, Larry's score was 120 pins, Moe's score was 240 pins, and Curly's score was 230 pins.