Question

In the triangle below, ∠Q is a right angle. Which ratio would be equivalent to the ratio of sin∠R?

a) cos∠Q
b) cos∠S
c) sin∠Q
d) sin∠S

Answer 1

cos<Q

Lets do

`\\ \sf\longmapsto sin<R=(P)/(H)`

`\\ \sf\longmapsto sin<R=(SQ)/(SR)`

Now

`\\ \sf\longmapsto cos<Q=(B)/(H)`

`\\ \sf\longmapsto cos<Q=(SQ)/(SR)`

Answer 2

• b) cos∠S

Explanation:

sin ∠R = SQ/SR

This is same as:

• cos S

Correct option is b)