Final answer:
The equation of the line parallel to the given line and passing through the point (1, -5) is y = 3x - 8.
Step-by-step explanation:
To write the equation of the line in slope-intercept form that is parallel to the given line and passes through the point (1, -5), we first need to know the slope of the given line.
From Figure A1, we know that the slope (m) of the line is 3. Since parallel lines have equal slopes, the new line will also have a slope of 3.
The slope-intercept form of a line is given by y = mx + b, where m is the slope and b is the y-intercept.
We can substitute the slope of 3 and the point (1, -5) into the equation to find b.
Plugging in these values gives us -5 = 3(1) + b. Solving for b, we find that b = -8.
Therefore, the equation of the line that is parallel to the given line and passes through the point (1, -5) is y = 3x - 8.