asked 201k views
1 vote
A ball is thrown up in the air from the top of a building. The function h(t) = -522 + 10t + 80 models the height of the ball, in feet, after t seconds. Graph this function. What is the maximum height reached by the ball?

Option 1: 90 ft
Option 2: 80 ft
Option 3: 85 ft
Option 4: 75 ft

asked
User Lukyer
by
8.5k points

1 Answer

3 votes

Final answer:

The function h(t) = -522 + 10t + 80 models the height of the ball thrown up in the air. The graph will be a linear line that increases by 10 units for every 1 unit increase in t. There is no maximum height reached by the ball in this scenario.

Step-by-step explanation:

To graph the function h(t) = -522 + 10t + 80, we can plot points on a coordinate plane using different values of t and calculate the corresponding h(t) values.

The graph will be a line that starts at -522 and increases by 10 units for every 1 unit increase in t. The maximum height reached by the ball can be determined by finding the vertex of the quadratic equation. Since the function given is linear, the maximum height is not applicable.

Therefore, none of the options provided (90 ft, 80 ft, 85 ft, 75 ft) are correct.

answered
User Rakwaht
by
8.1k points
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