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How many grams of Ca(OH), are needed to produce 500 mL of a 1.66 M

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User Wilman
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Final answer:

To calculate the number of grams of CaCl₂ needed to produce a certain molarity of solution, use the formula: grams = (molarity x volume x molar mass) / 1000. In this case, approximately 5.5245 grams of CaCl₂ are needed to produce 250.0 mL of a 0.200-M solution of calcium chloride.

Step-by-step explanation:

To calculate the number of grams of CaCl₂ needed to produce a certain molarity of solution, we can use the formula:

grams = (molarity x volume x molar mass) / 1000

In this case, the molarity is 0.200 M, the volume is 250.0 mL (which should be converted to liters), and the molar mass of CaCl₂ is 110.98 g/mol. Plugging in these values, we get:

grams = (0.200 mol/L x 0.250 L x 110.98 g/mol) / 1000 = 5.5245 g

Therefore, approximately 5.5245 grams of CaCl₂ are needed to produce 250.0 mL of a 0.200-M solution of calcium chloride.

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