Question

Two students travel from school to their jobs at the bowling alley, which is 2.5 km away. One student rides a scooter at 9.0 m/s, and the other student rides a bike at 12 mi/hr. Who arrives at the bowling alley first?

Answer 1

The student riding the scooter arrives at the bowling alley first, taking 277.8 seconds compared to the bike rider's time of 466.6 seconds.

Step-by-step explanation:

To determine which student arrives at the bowling alley first, we need to calculate the time it takes for each student to travel the distance of 2.5 km.

For the student riding the scooter, the time can be calculated using the formula:

time = distance / speed

Plugging in the values, we get:

time = 2.5 km / 9.0 m/s

Converting km to m, we have:

time = 2500 m / 9.0 m/s = 277.8 seconds

Now let's calculate the time for the student riding the bike:

time = 2.5 km / (12 mi/hr × 0.44704 m/s)

Converting mi/hr to m/s, we have:

time = 2.5 km / 5.36448 m/s = 466.6 seconds

Therefore, the student riding the scooter arrives at the bowling alley first, with a time of 277.8 seconds compared to the bike rider's time of 466.6 seconds.