Question

A bag contains five white marbles, three green marbles, and six red marbles. What are the odds in favor of randomly picking two red marbles in the first two tries? Assume that the first marble picked is not put back into the bag.

a) 10/27
b) 15/49
c) 18/49
d) 6/27

Answer 1

The odds in favor of randomly picking two red marbles in the first two tries are 15/91.

Step-by-step explanation:

To find the odds in favor of randomly picking two red marbles in the first two tries, we need to calculate the probability of picking two red marbles out of the total marbles in the bag.

There are 6 red marbles out of a total of 5+3+6 = 14 marbles in the bag.

The probability of picking a red marble on the first try is 6/14. After removing the red marble, there are 13 marbles left in the bag, with 5 red marbles.

The probability of picking a red marble on the second try is 5/13.

To find the odds in favor, we multiply the probabilities: (6/14) * (5/13) = 30/182 = 15/91