Question

The coordinate points of triangle ABC are

A (5,0), B (2,1), and C (-4,-4).
The triangle is translated 8 units right and 5 units down. What are the coordinates of the resulting triangle A'B'C'?

Answer 1

The coordinates of the resulting triangle A'B'C' after translation are A' (13, -5), B' (10, -4), C' (4, -9).

Step-by-step explanation:

To find the coordinates of the resulting triangle A'B'C', we need to translate each vertex of the original triangle by the given amounts.

A (5, 0) translated 8 units right and 5 units down becomes A' (5 + 8, 0 - 5) = A' (13, -5).

B (2, 1) translated 8 units right and 5 units down becomes B' (2 + 8, 1 - 5) = B' (10, -4).

C (-4, -4) translated 8 units right and 5 units down becomes C' (-4 + 8, -4 - 5) = C' (4, -9).