Question

The 3 busiest airports in the U. S. are Atlanta's Hartsfield-Jackson, Chicago's O'Hare, and New York City's Kennedy airports. If Chicago's airport has 1.36 million more that New York's airport and Atlanta's airport has .71 million less than twice that of New York's airport, write the sum of the number of passengers of all 3 airports if x is the number of people at New York's airport.

Answer 1

To find the sum of the number of passengers at all three airports, the number of passengers at each airport needs to be expressed in terms of x. The sum can be simplified to 4x + 0.65 million.

Step-by-step explanation:

To find the sum of the number of passengers at all three airports, we need to first express the number of passengers at each airport in terms of x, which represents the number of people at New York's airport.

Chicago's airport has 1.36 million more passengers than New York's airport, so the number of passengers at Chicago's airport would be x + 1.36 million.

Atlanta's airport has 0.71 million less than twice the number of passengers at New York's airport, so the number of passengers at Atlanta's airport would be (2 * x) - 0.71 million.

The sum of the number of passengers at all three airports would be x + (x + 1.36 million) + ((2 * x) - 0.71 million).

This can be simplified to 4x + 0.65 million.