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Translate the following C code to MIPS assembly code. Use a minimum number of instructions. Assume that the values of a,b,i, and j are in registers $s0,$s1,$t0, and $t1, respectively. Also, assume that register $2 holds the base address of array D. for (i=0;i

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Final answer:

The MIPS assembly code initializes a loop that compares variables 'i' and 'j', and within this loop, it stores the comparison result of 'a' and 'b' into the array D at the current index 'i'.

Step-by-step explanation:

The given C code suggests a loop that would iterate based on the changing value of i and compare it with the variable j. Within MIPS assembly, we would start the loop by setting i to 0, then continuously check if i is less than j, and within the loop, compare a with b and store the result in array D at the index i.

MIPS Translation

move $t0, $zero # i = 0

loop_start: bge $t0, $t1, loop_end # if i>=j, exit loop

sll $t2, $t0, 2 # t2 = i*4 (since an int is 4 bytes)

add $t2, $t2, $2 # t2 = address of D[i]

sle $t3, $s0, $s1 # t3 = (a <= b)

sw $t3, 0($t2) # D[i] = (a <= b)

addi $t0, $t0, 1 # i = i + 1

j loop_start # jump to start of loop

loop_end:

Please note that the sle instruction sets the destination register to 1 if the first source register is less than or equal to the second source register, and 0 otherwise. We then store this result into the appropriate index of array D.

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