Question

There are three integers. The first is twice as large as the second, and the second is twice as large as the third. The total of the integers is 161. What is the smallest of those integers

Answer 1

The smallest integer is found by setting up an equation where it's represented by x, the second integer as 2x, and the third as 4x, and solving for x in the equation x + 2x + 4x = 161, which yields the smallest integer as 23.

Step-by-step explanation:

Let's denote the smallest integer as x. Therefore, the second integer is 2x (twice as large as the third), and the first integer is 4x (twice as large as the second, which is already 2x).The sum of these integers is given as 161, so we can write the equation: x + 2x + 4x = 161. Combining like terms, we get 7x = 161. Dividing both sides by 7 yields x = 23.

Therefore, the smallest of the three integers is 23.