asked 57.0k views
5 votes
Find the equation of the line that is perpendicular

-3
V= x - 77
to
2 and passes through the point
(12,-2)

asked
User Rien
by
8.4k points

1 Answer

5 votes

Final answer:

The question contains a typo in the equation of the line to which a line should be perpendicular, preventing us from calculating the equation of the desired perpendicular line. However, the general process involves finding the slope of the original line, determining the negative reciprocal for the perpendicular line's slope, and then applying the point-slope formula using the given point.

Step-by-step explanation:

To find the equation of the line that is perpendicular to the given line and passes through the point (12, -2), first, we determine the slope of the given line. However, there seems to be a typo in the given equation 'perpendicular-3V= x - 77to2'. Assuming it is meant to be a linear equation in the form y = mx + b, where 'm' is the slope and 'b' is the y-intercept, we need the correct form of the equation to proceed.

Once we have the correct equation and thus the slope of the given line, we can find the slope of the perpendicular line by taking the negative reciprocal of the given line's slope. After obtaining the slope of the perpendicular line, we can use the point-slope form of a line (y - y1) = m(x - x1), where m is the slope and (x1, y1) is the given point (12, -2), to find the equation of our new line.

Due to the error in the provided equation, we cannot proceed with the calculation, but the process has been described above.

answered
User Dhaval Jotaniya
by
7.6k points

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