Question

For the quadratic function f(x) = 2x²– 8x +1 what is f(-1) ?

Answer 1

f(-1) = 11. When substituting -1 into the function f(x) = 2x² – 8x + 1, the result is 11.

Explanation:

To find f(-1) for the quadratic function f(x) = 2x² – 8x + 1, substitute -1 into the function:

f(-1) = 2(-1)² – 8(-1) + 1

f(-1) = 2(1) + 8 + 1

f(-1) = 2 + 8 + 1

f(-1) = 11

In the given quadratic function, f(x) = 2x² – 8x + 1, plugging in x = -1 gives us the value of the function at that point. By replacing x with -1 in the function, following the order of operations (PEMDAS/BODMAS), which stands for Parentheses/Brackets, Exponents/Orders, Multiplication and Division, and Addition and Subtraction, we solve for f(-1). After substituting -1 into the equation, we simplify the expression step by step to get the final result.

Therefore, when x = -1, the value of the function f(x) = 2x² – 8x + 1 is 11.

Answer 2

For the quadratic function
`\(f(x) = 2x^2 - 8x + 1\)`, when
`\(x = -1\)`,
`\(f(-1) = 11\)`.

Step-by-step explanation:

In the given quadratic function
`\(f(x) = 2x^2 - 8x + 1\)`, the expression
`\(f(-1)\)` represents the value of the function when
`\(x\)` is replaced with
`\(-1\)`. To find this value, substitute
`\(-1\)` for
`\(x\)` in the function:

`\[f(-1) = 2(-1)^2 - 8(-1) + 1\]`

Simplifying the expression step by step:

`\[f(-1) = 2(1) + 8 + 1\]`

`\[f(-1) = 2 + 8 + 1\]`

`\[f(-1) = 11\]`

Therefore,
`\(f(-1)\)` is equal to
`\(11\)`. This means that when
`\(x\)` is
`\(-1\)`, the corresponding
`\(y\)` value (or
`\(f(x)\)` ) is
`\(11\)`.

In summary, by substituting
`\(-1\)` into the quadratic function, we find that
`\(f(-1)\)` equals
`\(11\)`. This process involves plugging in the given value for
`\(x\)` and simplifying the expression to obtain the final result.