Final answer:
The wavelength of light with a frequency of 3.31E+14 Hz is 906 nm.
Step-by-step explanation:
The wavelength of light that has a frequency of 3.31E+14 Hz can be determined using the formula c = fλ, where c is the speed of light in a vacuum (3.00 × 108 m/s), f is the frequency, and λ is the wavelength. To find the wavelength (λ), rearrange the equation to λ = c / f. With the given frequency, the calculation would be λ = (3.00 × 108 m/s) / (3.31 × 1014 Hz).
Performing the division, the wavelength of this light is λ = 9.06 × 10-7 meters, which can also be expressed as 906 nm (nanometers), assuming that 1 nm = 1 × 10-9 m.