asked 222k views
4 votes
BGE is a triangle such that BG = GE. Show that the angle marked x is 80°.

ignore my markings they r prolly wrong

asked
User Falstro
by
7.8k points

1 Answer

7 votes

Final answer:

The angle marked x is 80°. angle BGE and angle EGB are congruent. Considering the sum of angles in a triangle is 180°, and given that angle BGE = angle EGB = x, the total of these two angles is 2x. As BG = GE, angle BGE = angle EGB = x = 40°.

Explanation:

In triangle BGE where BG = GE, the angles opposite equal sides are also equal. Therefore, angle BGE and angle EGB are congruent. Considering the sum of angles in a triangle is 180°, and given that angle BGE = angle EGB = x, the total of these two angles is 2x. As BG = GE, angle BGE = angle EGB = x = 40°.

Hence, angle x, marked in the diagram, is 80° (2x = 2 * 40° = 80°). This is derived from the fact that the angles around point G add up to 180°, and in this case, the three angles are x, x, and 60° (as they form a straight line), leading to x = 40°, making the marked angle x equal to 80°.

The angle marked x is 80°. angle BGE and angle EGB are congruent. Considering the sum of angles in a triangle is 180°, and given that angle BGE = angle EGB = x, the total of these two angles is 2x. As BG = GE, angle BGE = angle EGB = x = 40°.

answered
User Maxim Petlyuk
by
8.6k points
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