Final answer:
Using Henry's law, the new solubility of the gas in water when the pressure is increased to 115 kPa is calculated to be 1.0 g/L, corresponding to option A.
Step-by-step explanation:
The question refers to the solubility of a gas in water at different pressures, which can be calculated using Henry's law. According to Henry's law, the solubility of a gas in a liquid at a constant temperature is directly proportional to the pressure of the gas above the liquid. The initial solubility is given as 0.2 g/L at a pressure of 23.5 kPa, and we are asked to find the new solubility at a pressure of 115 kPa.
The formula based on Henry's law is S1/P1 = S2/P2, where S1 and S2 are the gas solubilities at pressures P1 and P2, respectively. Substituting the known values into this formula:
S2 = (S1 x P2) / P1
= (0.2 g/L x 115 kPa) / 23.5 kPa
= 0.978 g/L, which can be rounded to 1.0 g/L.
Therefore, the solubility of the gas in water when the pressure is increased to 115 kPa is 1.0 g/L, which corresponds to option A.