Question

If an object is thrown upward with an initial velocity of 128 ​ft/second, then its height after t seconds is given by the following equation. h equals 128 t minus 32 t squared Find the maximum height attained by the object.

Answer 1

The maximum height attained by the object is 128 feet.

Step-by-step explanation:

The maximum height attained by the object can be determined by finding the vertex of the quadratic equation h = 128t - 32t^2.

The vertex of a quadratic equation in the form ax^2 + bx + c is given by the formula x = -b / (2a).

In this case, a = -32 and b = 128.

Plugging these values into the formula, we get t = -128 / (2(-32)) = 2 seconds.

Substituting t = 2 back into the equation to find h, we get h = 128(2) - 32(2)^2 = 256 - 128 = 128 feet.

Therefore, the maximum height attained by the object is 128 feet.