asked 159k views
5 votes
two spherical conducting shells of radii a and b (b>a) are separated by a material with conductivity. find an expression for the resistance between the two spheres.

asked
User Eythort
by
8.3k points

1 Answer

3 votes

The expression for the resistance (R) between two spherical conducting shells of radii a and b (with b>a) separated by a material with conductivity is 1/4πσ( 1/a-1/b), where σ is the conductivity of the material.

The expression for the resistance (R) between two spherical conducting shells of radii a and b (with b>a) separated by a material with conductivity can be derived based on the formula for the resistance of a cylindrical conductor. In this case, the cylindrical conductor is represented by the material between the two shells.

The resistance of the cylindrical section is given by R= ρL/A, where ρ is the resistivity, L is the length, and A is the cross-sectional area. Considering a thin cylindrical shell between the two spheres, the length (L) is the radial separation between the shells, and the cross-sectional area (A) is 2πrdr, where r is the radial distance from the center.

Integrating this expression over the radial distance from a to b provides the total resistance (R). Utilizing the conductivity (σ= 1/ρ), the final expression for the resistance between the two spherical conducting shells is 1/4πσ( 1/a-1/b). This expression encapsulates the influence of the material's conductivity and the geometrical configuration of the two spherical shells on the overall resistance between them.

answered
User Mptevsion
by
8.6k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.