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Solve 2x^2+x-4=0

x^2+___x+___=0

Solve 2x^2+x-4=0 x^2+___x+___=0-example-1

1 Answer

4 votes

Final answer:

Using the quadratic formula in the given equation, the solutions are 1/2 and -1.

Step-by-step explanation:

To solve the equation 2x^2+x-4=0, we can use the quadratic formula.

The quadratic formula states that for an equation of the form ax^2+bx+c = 0, the solutions for x can be calculated using the formula:

x = (-b ± √(b^2-4ac)) / (2a)

For the given equation, a=2, b=1, and c=-4.

Plugging these values into the quadratic formula, we get:

x = (-1 ± √(1^2-4*2*(-4))) / (2*2)

This simplifies to:

x = (-1 ± √(9)) / 4

Therefore, the solutions for the equation are:

x = (-1 + 3) / 4

= 2/4

= 1/2

x = (-1 - 3) / 4

= -4/4

= -1.

answered
User Sumesh TG
by
8.4k points

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