asked 203k views
2 votes
how many nonzero terms are in the expansion of$$(x 4)(2x^2 3x 9)-3(x^3-2x^2 7x)?$$ your first answer: 0

1 Answer

1 vote

Final answer:

To determine the number of nonzero terms in the expansion of the given expression, we need to distribute and simplify. After expanding and combining like terms, we find that the expression has 4 nonzero terms.

Step-by-step explanation:

To determine the number of nonzero terms in the expansion of the given expression, we need to distribute and simplify. Let's start with the first term:

(x + 4)(2x^2 + 3x + 9)

Expanding:

2x^3 + 3x^2 + 9x + 8x^2 + 12x + 36

Combining like terms:

2x^3 + 11x^2 + 21x + 36

Now let's focus on the second term:

-3(x^3 - 2x^2 + 7x)

Distributing:

-3x^3 + 6x^2 - 21x

Combining like terms:

-3x^3 + 6x^2 - 21x

Adding the two simplified terms together:

2x^3 + 11x^2 + 21x + 36 + (-3x^3 + 6x^2 - 21x)

Combining like terms:

-x^3 + 17x^2 + 15x + 36

Therefore, the number of nonzero terms in the expansion is 4.

answered
User Buttonsrtoys
by
7.4k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.