asked 198k views
1 vote
What is the value of the 4th term of the expansion of (y+2z)^8

1 Answer

1 vote

Answer:

448y^5z^3.

Explanation:

(r+1)the term of (a + b)^n

= nCr a^(n-r) b^r

So here we have

4th term = 8C3 y^(8-3) (2z)^3

= 56y^5*8z^3

= 448y^5z^3.

answered
User Wim Leers
by
8.0k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.