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If the area of the larger square is 100 and the area of the smaller square is 36, What is y?

1 Answer

2 votes

Final answer:

The value of y is 6.

Step-by-step explanation:

To compare the areas of the larger and smaller squares, we need to find the lengths of their sides. Let's denote the side length of the larger square as x, and the side length of the smaller square as y. We are given that the area of the larger square is 100, so we can write the equation x^2 = 100. Solving for x, we find x = 10.

Similarly, we are given that the area of the smaller square is 36, so we can write the equation y^2 = 36. Solving for y, we find y = 6.

To find the value of y, we can substitute the value of x into the equation y^2 = 100. This gives us 6^2 = 100, which simplifies to 36 = 100. Therefore, y = 6.

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User Richyen
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