Question

Suppose an electric current of 1.5 microamps were to go through a resistance of 2.3 megaohms. How much voltage would be dropped across this resistance?

a) 3.45 volts
b) 345 volts
c) 0.00345 volts
d) 0.00000345 volts

Answer 1

The voltage dropped across a resistance with a current of 1.5 microamps and a resistance of 2.3 megaohms is calculated using Ohm's law (V = IR) to be 3.45 volts.

Step-by-step explanation:

To find the voltage dropped across a resistance when current is flowing through it, we use Ohm's law. Ohm's law states that the voltage (V) across a resistor is equal to the product of the current (I) flowing through it and the resistance (R) of the resistor, expressed by the formula V = IR. In this case, we have a current of 1.5 microamps (1.5 x 10-6 amps) and a resistance of 2.3 megaohms (2.3 x 106 ohms). Multiplying these values gives us the voltage drop: V = I x R = (1.5 x 10-6 A) x (2.3 x 106 Ω) = 3.45 volts Therefore, the correct answer is a) 3.45 volts.