Question

The specific heat of water is 4,186 J/kg.'C. Approximately how much heat must

be removed from 0.500 kg of water to change its temperature from 24.0°C to
5.00°C?

Answer 1

Step-by-step explanation:

Q= mc∆T

∆T= 5-24=- 19

Q= 0.5*4186*-19

Q= -39767 J

negative sign show heat releases