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Inductive reactance of a given circuit is −Q, what must be done to correct the power factor to a value of 1?

1 Answer

4 votes

Final answer:

To correct the power factor to 1, a capacitor must be placed in series with the circuit. The value of the reactance across the inductor that will raise the power factor to unity can be calculated using the formula Xc = 1 / (2πfC).

Step-by-step explanation:

To correct the power factor to a value of 1, a capacitor must be placed in series with the circuit. This is because the given circuit has an inductive reactance of -Q, which means it has a lagging voltage. By adding a capacitor, it will provide a leading voltage, thereby correcting the power factor.

The value of the reactance across the inductor that will raise the power factor to unity can be calculated using the formula:

Xc = 1 / (2πfC)

Where Xc is the capacitive reactance, f is the frequency, and C is the capacitance. By substituting the values into the formula, you can find the required reactance.

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User Bengel
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