Question

A perfect gas undergoes isothermal compression, which reduces its volume by 2.2 dm3 . The final pressure and volume of the gas are 1.97 bar and 2.14 dm3 , respectively. Calculate the original pressure of the gas and write down the unit in bar. Hint: isothermal compression means that the temperature is maintained unchanged during the compression process.

Answer 1

The original pressure of the gas is 1.912 bar.

Step-by-step explanation:

To find the original pressure of the gas, we can use Boyle's law, which states that for an isothermal process, the product of pressure and volume is constant.

We can write the equation as:

P1 × V1 = P2 × V2

Plugging in the values given:

P1 × (2.2 dm3) = (1.97 bar) × (2.14 dm3)

Solving for P1:

P1 = (1.97 bar × 2.14 dm3) / (2.2 dm3)

Calculating the value:

P1 = 1.912 bar

Therefore, the original pressure of the gas was 1.912 bar.