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625mol of a gas in a 45.4L container at -24.0°C exerts a pressure of what

atm.

A. 1.53 atm
B. 2.23 atm
C. 3.12 atm
D. 0.93 atm

1 Answer

2 votes

Final answer:

To find the pressure of the gas in the container, we can use the ideal gas law equation: PV = nRT. represents the pressure, V represents the volume, n represents the number of moles, R is the gas constant, and T represents the temperature in Kelvin. By substituting the given values and solving for P, we find that the pressure is approximately 2.23 atm.

Step-by-step explanation:

To solve this question, we can use the ideal gas law equation: PV = nRT. P represents the pressure, V represents the volume, n represents the number of moles, R is the gas constant, and T represents the temperature in Kelvin. We need to convert the given temperature of -24.0°C to Kelvin by adding 273.15. So, T = -24.0°C + 273.15 = 249.15 K. Substituting the values into the equation, we get (P)(45.4L) = (625mol)(0.0821 L·atm/(mol·K))(249.15K). By solving for P, we find that the pressure is approximately 2.23 atm. Therefore, the correct answer is B. 2.23 atm.

the pressure of the gas in the container, we can use the ideal gas law equation: PV = nRT. represents the pressure, V represents the volume, n represents the number of moles, R is the gas constant, and T represents the temperature in Kelvin. By substituting the given values and solving for P, we find that the pressure is approximately 2.23 atm.

answered
User Badlogic
by
8.2k points
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