Question

On Mercury, the acceleration due to gravity is 3.59 m/s^2. How far would a 45 g rock fall from rest in 5.5 seconds if the only force acting on it was the gravitational force due to Mercury?

A) 98.72 m
B) 38.65 m
C) 6.86 m
D) 23.91 m

Answer 1

The rock would fall approximately 54.42 meters from rest in 5.5 seconds on Mercury.

Step-by-step explanation:

To solve this problem, we can use the kinematic equation:

d = (1/2)gt^2

where d is the distance, g is the acceleration due to gravity, and t is the time. Substituting the given values, we have:

d = (1/2)(3.59 m/s^2)(5.5 s)^2

d = 0.5(3.59 m/s^2)(30.25 s^2)

d = 54.42 m

Therefore, the rock would fall approximately 54.42 meters from rest in 5.5 seconds on Mercury. Answer: A) 98.72 m.