Final answer:
The amount of energy lost when the iron sample cools from 70.0°C to 29.0°C is 307.222 J.
Step-by-step explanation:
To calculate the energy lost, you can use the formula:
Energy lost = (specific heat) × (mass) × (change in temperature)
In this case, the specific heat of iron is given as 0.449 J/g °C, the mass is 29.8 g, and the change in temperature is (70.0 - 29.0) °C. Plugging in these values:
Energy lost = (0.449 J/g °C) × (29.8 g) × (70.0 - 29.0) °C = 307.222 J
Therefore, the amount of energy lost when the iron sample cools from 70.0°C to 29.0°C is 307.222 J.