Question

Find three consecutive negative integers such that the product of the median integer and the smallest integer is 210.

A) -7, -8, -9
B) -5, -6, -7
C) -6, -7, -8
D) -8, -9, -10

Answer 1

To find three consecutive negative integers such that the product of the median integer and the smallest integer is 210, let the integers be represented as (x), (x+1), and (x+2). Solve the equation x * (x+1) = 210 to find the values of x.

Step-by-step explanation:

To find three consecutive negative integers such that the product of the median integer and the smallest integer is 210, we can let the integers be represented as (x), (x+1), and (x+2). According to the given condition, we have the equation x * (x+1) = 210. Solving this equation, we find that the solutions are x = -7, x+1 = -8, and x+2 = -9. Therefore, the three consecutive negative integers are -7, -8, and -9, which matches option A.