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The longest passenger liner ever built was the France, 66,348 tons and 315.5 m long. Suppose its front end passes the edge of a pier at a speed of 2.9 m/s while the ship is accelerating uniformly at 0.04 m/s². At what speed will the back end of the vessel pass the pier?

a. 2.63 m/s
b. 2.87 m/s
c. 3.13 m/s
d. 3.37 m/s

1 Answer

6 votes

Final answer:

The speed at which the back end of the passenger liner will pass the pier can be calculated using the uniform acceleration formula by first determining the time it takes for the ship's entire length to pass the pier, then plugging that time into the formula for final velocity.

Step-by-step explanation:

The student is asking for the final speed at which the back end of a passenger liner will pass the pier, given its initial speed and uniform acceleration. To calculate this, we can use the formula for final velocity in uniformly accelerated motion, which is v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.

However, the value of time is not directly given, so we first need to determine the time t that it takes for the entire length of the ship to pass the pier. This can be calculated by dividing the length of the ship by the initial velocity: t = L/u, where L is the length of the ship (315.5 m) and u is the initial velocity (2.9 m/s). After calculating t, we can then use it in the formula for final velocity to find the speed at which the back end of the ship passes the pier.

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User Aaron Wojnowski
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