Question

How many grams of aluminum hydroxide are produced when 8 moles of aluminum sulfite react in excess sodium hydroxide ?

Answer 1

Number of moles Aluminium sulfide

1 mole of sulfide contains 150 g

Therefore; 16.2/150

= 0.108 moles

The mole ratio of Al2S3 : Al(OH)3 is 1:2

Therefore; moles of Aluminium hydroxide will be;

= (0.108 × 2)

= 0.216 moles

But, 1 mole of Al(OH)3 contains 77 g

Therefore, the mass of aluminium hydroxide is

0.216 moles × 77

= 16.632 g

Explanation: