The line segment A'B' is attached and the perimeter is 26.2 units
Graphing the line segment A'B' and calculating the perimeter
From the question, we have the following parameters that can be used in our computation:
A(3, 3) and B(6,-3)
The reflection of the point (x, y) across the line y = x is (y, x)
So, we have
A'(3, 3) and B'(-3, 6)
From the graph, we can see that the figure formed is a triangle with the side lenghts
A = √(3² + 6²) = 6.71
B = √(3² + 6²) = 6.71
C = √(9² + 9²) = 12.73
So, the Perimeter is
P = 6.71 + 6.71 + 12.73
P = 26.2
Hence, the perimeter is 26.2 cm